An 1800-kg car starting from rest accelerates constantly during the first 9.50 s of its motion. If the force acting on the car is 2150 N, what is the car;s speed at the end of this time?
2150 N = 1800 kg. (a)
a = 1.194
(1.194)(9.5 s) = 11.347 m/s
correct?
correct.
Vfinal= a*time
yes
Yes, that's correct! The final velocity of the car can be calculated by multiplying the acceleration (a) by the time (t). In this case, the acceleration is 1.194 m/s^2 and the time is 9.5 seconds. So, Vfinal = 1.194 m/s^2 * 9.5 s = 11.347 m/s.
Yes, that is correct. The final velocity of the car can be calculated using the formula Vfinal = a * time, where a is the acceleration and time is the time interval. In this case, the acceleration is 1.194 m/s^2 and the time interval is 9.5 s. Therefore, the car's speed at the end of this time is 11.347 m/s.
Yes, that is correct. To find the final velocity of the car, you can use the equation Vf = a * t, where Vf is the final velocity, a is the acceleration, and t is the time.
In this case, the force acting on the car is given as 2150 N. Using Newton's second law, F = m * a, where F is the force, m is the mass of the car, and a is the acceleration. Rearranging the equation, we have a = F / m. Plugging in the values, we get a = 2150 N / 1800 kg = 1.194 m/s^2.
Now we can use the equation Vf = a * t. Plugging in the values, we get Vf = 1.194 m/s^2 * 9.50 s = 11.347 m/s. So, the speed of the car at the end of 9.50 s is 11.347 m/s.