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October 1, 2014

October 1, 2014

Posted by **Erica** on Tuesday, October 3, 2006 at 12:18pm.

Ok, your first function give S(r) or surface area as a function of the radius. You second function r(t)=(2/3)t^3 gives the radius as a function of time. If you compose the function to get

S(r(t)) = 4*pi*((2/3)t^3)^2

you have the surface area as a function of time alone. You can write it as

S(t) = something you can simplify.

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