Posted by **tigger needs help** on Tuesday, October 3, 2006 at 10:20am.

hi this is my problem...

A shaft turning at the 1800 r/min is coupled to a gear with 80 teeth, matching a gear with 62 teeth. In turn this gear is fitted to an intermediate shaft driving a gear with 40 teeth. This gear in turn drives a gear with 96 teeth...Calculate the final gear's rotational frequency.

P.S.:If the guy who's helping me is interested i would like it if we could help each other by means of a chatroom

One just multiplies..

1800*80/62*62/40*40/96

Notice in general you can ignore the intermediate gears...

1800*80/96 would have worked just as well.

thanx can cus chatrooms it would go quiker for me

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