λ for one line of the hydrogen spectrum is .4118 x 10-4 cm. Use this value in the Rydberg equation to calculate the RH value using n1 = 2, and n2 = 5.

change the line spectrum to meters

you know the equation is Et= Ef-Ei (i think is the equation they want you to use, i don't know what they want),
well then that would be (-Rhc/nf^2)-(-Rhc/ni^2)

Rhc= 2.179 Z 10^-18 J/atom or
1312 kJ/mol

if this isnt the equation you needed sorry

This is a double post.

To calculate the RH value using the Rydberg equation, we will first convert the given wavelength to meters.

Given: λ = 0.4118 x 10^(-4) cm

To convert cm to meters, we need to multiply by a conversion factor:
1 cm = 0.01 meters

Therefore, λ = (0.4118 x 10^(-4)) * 0.01 = 4.118 x 10^(-6) meters.

Now, we can proceed with the Rydberg equation:

1/λ = RH * (1/n1^2 - 1/n2^2)

Substituting the values:
n1 = 2, n2 = 5, and λ = 4.118 x 10^(-6) meters.

We can rearrange the equation to solve for RH:

RH = 1/λ * (1/n1^2 - 1/n2^2)

RH = (1 / 4.118 x 10^(-6)) * (1/2^2 - 1/5^2)

RH = (1 / 4.118 x 10^(-6)) * (1/4 - 1/25)

RH = (1 / 4.118 x 10^(-6)) * (25/100 - 4/100)

RH = (1 / 4.118 x 10^(-6)) * (21/100)

RH = 2.563 x 10^(15) m^(-1)

Therefore, the RH value using n1 = 2 and n2 = 5 is approximately 2.563 x 10^(15) m^(-1).