i thought i had the answer right, but i didnt! wat are the first few steps?? an elevator (mass 4850kg) is to be designed so that the maximum acceleration is .0680g. what are the maximum and minimum forces the motor should exert on the supporting cable? i know the answers but don't know how to come up with the work! (max=5.08*10^4N and min=4.43*10^4N)
Goodness. Did you read my response?
Tension= m(g +- a)
Consider the max...
Tension= 4850*( 1.068*9.80665)= you do it.
I am not certain of what you have been instructed to use for g.
To find the maximum and minimum forces the motor should exert on the supporting cable for the elevator, you will need to use the equation for tension in the cable:
Tension = mass * (gravity ± acceleration)
Where:
- Tension is the force exerted on the cable,
- mass is the mass of the elevator (given as 4850 kg),
- gravity is the acceleration due to gravity (approximately 9.8 m/s^2), and
- acceleration is the maximum acceleration of the elevator (given as 0.068 times the acceleration due to gravity).
To find the maximum force, you need to use the "+" sign with the acceleration value:
Tension_max = 4850 kg * (9.8 m/s^2 + 0.068 * 9.8 m/s^2)
To find the minimum force, you need to use the "-" sign with the acceleration value:
Tension_min = 4850 kg * (9.8 m/s^2 - 0.068 * 9.8 m/s^2)
Evaluating these equations, you will get:
Tension_max = 4850 kg * (1.068 * 9.8 m/s^2) ≈ 5.08 * 10^4 N
Tension_min = 4850 kg * (0.932 * 9.8 m/s^2) ≈ 4.43 * 10^4 N
So, the maximum force the motor should exert on the supporting cable is approximately 5.08 * 10^4 Newtons, and the minimum force is approximately 4.43 * 10^4 Newtons.