# Calculus...again

posted by
**Tezuka** on
.

I'm gonna have abunch of questions, cause I have a test. >_<

If you planened to fence a rectangular pasture that must contain 4000 sq meters, what dimensions would require the least amount of fencing?

Perimeter= 2l + 2w

area= lw=4000

or l=4000/w

P= 2(4000/w + w)

Now minimize this function, solve for w.