Posted by ronan on .
f(x) = 1/(x^2-x-2)
does f(x) have two or three asymptotes
does f(x) have one or two discontinuities
We have f(x) = 1/(x^2-x-2) or
f has vert. asympt. at the roots of the denominator.
As x becomes unbounded in either direction you should be able to see that it approaches the x-axis.
So 2 vertical and 1 horizntal asymptote = 3 asymptotes, and 2 roots = 2 discontinuities.