Monday

December 22, 2014

December 22, 2014

Posted by **Anonymous** on Friday, September 29, 2006 at 6:05pm.

log5(x-4)= log7x solve for x.

These are just base 10 logs.

log100 = 2

This equation has the same format as log 40 = log (2x20)

Since both sides have log base 10, you divide by log base 10 and end up with 5(x-4) = 7x, so 5x -20 =7x x=-10

One doesn't

log5(x-4)= log7x solve for x.

take each side as exponents to the base 10, or

10^(log5(x-4))= 10^(log7x)

then

5(x-4) = 7x

and x= 10

check...

log (5(-14)= log -70

log (-70)=log(-70) and it checks

**Answer this Question**

**Related Questions**

Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...

math - solve for x without using a calculator 5^(x+1) = 25 i know that x would ...

algebra - logarithms Solve the following equations 3^x-2=6 Add 2 to both sides ...

LOGARITHMS - HI THE QUESTION STATES THAT ONE SHOULD CALCULATE THE LOGS WITHOUT ...

Math - My question says: Find the exact alue of x for which (4^x)*(5^[4x+3])=(10...

math - write as a single logarithm: -2logbase3(1/x)+(1/3)logbase3(square root of...

Algebra 2 - -Explain the difference between log base b (mn) and ( log base b of ...

math-logs - 1. logaB = 2 and logbC = 4, evaluate logcA *the lowercase letters ...

Trigonometry - This is a logs question If u=x/y^2, which expression is ...

Re: Algebra II - How to solve Log (9x+5) - Log ((x^2)-1) = 1/2 16 16 (The 16 is...