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April 24, 2014

April 24, 2014

Posted by **brian** on Wednesday, September 27, 2006 at 6:12pm.

y = (x-9) / sqr(4x^2 + 3x+ 2)

What happens to y as x goes to +/- infinity? Specifically, is y approaching some limit from above or below?

??

I see your question was to just find the horizontal asymptotes and not to evaluate the function's approach to them.

The denominator has no real zeroes, so it's always positive. For large x the denominator behaves like |x| and the numerator is just x. The limits that need to be checked are

lim x-> +/-infinity x/|x|

Does that help?

so

sqr(4x^2 + 3x +2) is equivalent to |x|

Check that, it for large x it behaves like 2|x| -I missed the 4.

thx

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