Posted by **lil** on Wednesday, September 27, 2006 at 3:54pm.

what is the derivative of sinx- cosy = 0 in its simplest form? I got to the point y'=-consx/siny, but I wasn't too sure. This could probably simplified further. help!

You're supposed to treat y as a function of x and differentiate it implicitly. We have

d/dx{sinx- cosy)=d/dx{sinx) - d/dx{cosy)=

cos(x)-(-sin(y)*y')=0

You should be able to solve for y'.

I did, and I ended up with y'=-cos(x)/sin(y)

How do I simplify this further?

That's as far as you can go unless you know something specific about y. Without knowing something about y(x) there's nothing else to do here.

## Answer This Question

## Related Questions

- Math - How do I get (sinx cosy + cosx siny) (cosx cosy + sinx siny) in the form ...
- Math - Suppose f(x) = sin(pi*cosx) On any interval where the inverse function y...
- trig - Okay, I've been getting some of these, but I can't seem to verify this ...
- Calc I - Find an equation of the tangent to the curve at the given point. y=4(...
- Trigonometry Help - Simplify: sin(x-y)cosy+cos(x-y)siny = (sinxcosy-cosxsiny)...
- MATH PLEASE CHECK IT!!2 - sqrt2/sqrt10 here is what I got: sqrt (2/10)= sqrt (1/...
- Trigonometry - Prove that (cosy/1+siny) + (1+siny/cosy) = 2secy
- math - sinx+ siny/ (cosx+cosy)= tan 1/2 (x+y) prove this identity
- Trigo help! - Ok, i've tried this question, and it brings me to no answers. ...
- Trigonometry - If Hello, I have been working on this one problem for a while now...

More Related Questions