how do i figure out this problem i have to make the equation true by inserting one or more parenthesis

a. 2 * 3^2 + 4 * 3 - 1 = 47

For this
a. 2 * 3^2 + 4 * 3 - 1 = 47
You need a fairly large number compared with the available numbers, so you might try grouping the 2 and 3 together before squaring them.

To figure out this problem and make the equation true by inserting one or more parentheses, follow these steps:

1. Start by looking at the equation: 2 * 3^2 + 4 * 3 - 1 = 47.
2. Notice that there are two operations: multiplication (*) and exponentiation (^).
3. The exponentiation operation, 3^2, should be done first according to the order of operations (PEMDAS/BODMAS).
4. Calculate 3^2, which is equal to 9.
5. Replace the exponentiation operation with its result: 2 * 9 + 4 * 3 - 1 = 47.
6. Now, you have only multiplication and addition/subtraction left.
7. Based on the equation, it seems that the multiplication should be done before the addition/subtraction.
8. Start by multiplying 2 * 9: 18 + 4 * 3 - 1 = 47.
9. Continue by multiplying 4 * 3: 18 + 12 - 1 = 47.
10. Finally, perform the addition and subtraction operations: 30 - 1 = 47.
11. The result is 29, which is not equal to 47. Therefore, the equation is currently not true.

To make the equation true by inserting one or more parentheses, let's try grouping the 2 and 3 together before squaring them.

12. Rewrite the equation: (2 * 3)^2 + 4 * 3 - 1 = 47.
13. Calculate the group inside the parentheses first: 6^2 + 4 * 3 - 1 = 47.
14. Square 6: 36 + 4 * 3 - 1 = 47.
15. Perform the remaining multiplication: 36 + 12 - 1 = 47.
16. Perform the addition and subtraction operations: 48 - 1 = 47.
17. The result is 47, which means that the equation is now true.

By inserting the parentheses to group 2 and 3 together before squaring them, you can make the equation true.