Tuesday

September 30, 2014

September 30, 2014

Posted by **Melba** on Tuesday, September 26, 2006 at 3:48pm.

Any ideas??

First express the line as in point slope form

y=(5/2)x - 21/2

The center must be on the line, so it is a point expressed as

(x,(5/2)x - 21/2)

In order for the circle to be tangent to both axis the center must be the same distance from both axis, so

x=y or x=(5/2)x - 21/2 solve for x

The standard equation for the circle is

(x-a)^2+(y-b)^2=r^2

You should be able to determine a,b and r.

After review, I don't know if I suggested how to find all the solutions.

You need to look at |x|=|y| or

|x|=|5/2)x - 21/2|

There should be one more solution to the question.

Thanks for all your help...

**Answer this Question**

**Related Questions**

Calc. - Find the area of the region bounded by the parabola y=x^2, the tangent ...

calculus - Consider line segments which are tangent to a point on the right half...

calc - The slope of the tangent line to the parabola y=4x2–3x+5 at the point ...

Calculus - Consider line segments which are tangent to a point on the right ...

Math - Write your answer in standard form. Show all your work if you want to be ...

Calc - The slope of the tangent line to the parabola y=4x2–3x+5 at the point ...

Algebra - I'm suppose to write an equation with the following information: Line ...

math - Find the slope and the intercepts of each line. g(x)=54x-1 x=-3 Help ...

MATH! - What type of lines have a slope of zero? Write the equation of a line ...

Geometry/Trigonometry - Circles with centers (2,1) and (8,9) have radii 1 and 9...