Posted by **Melba** on Tuesday, September 26, 2006 at 3:48pm.

standard equations of circles that have centers on line 5x-2y=-21 and are tangent to both axis.

Any ideas??

First express the line as in point slope form

y=(5/2)x - 21/2

The center must be on the line, so it is a point expressed as

(x,(5/2)x - 21/2)

In order for the circle to be tangent to both axis the center must be the same distance from both axis, so

x=y or x=(5/2)x - 21/2 solve for x

The standard equation for the circle is

(x-a)^2+(y-b)^2=r^2

You should be able to determine a,b and r.

After review, I don't know if I suggested how to find all the solutions.

You need to look at |x|=|y| or

|x|=|5/2)x - 21/2|

There should be one more solution to the question.

Thanks for all your help...

## Answer this Question

## Related Questions

- Calc. - Find the area of the region bounded by the parabola y=x^2, the tangent ...
- Math - Write your answer in standard form. Show all your work if you want to be ...
- Circles (Conic Sections) - I have no idea how to do these problems: Find an ...
- calculus - Consider line segments which are tangent to a point on the right half...
- Algebra - I'm suppose to write an equation with the following information: Line ...
- calc - The slope of the tangent line to the parabola y=4x2–3x+5 at the point ...
- Calculus - Consider line segments which are tangent to a point on the right ...
- Calc - The slope of the tangent line to the parabola y=4x2–3x+5 at the point ...
- Calc AB - Suppose that f(x) is an invertible function (that is, has an inverse ...
- math - Find the slope and the intercepts of each line. g(x)=54x-1 x=-3 Help ...

More Related Questions