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December 18, 2014

December 18, 2014

Posted by **Aliah** on Monday, September 25, 2006 at 8:46pm.

Who was ahead?_______________________

Help!

Assuming the distance of the jump is the same for each frog.

30 jumps x 25/jump = ??

30 jumps x 20/jump = xx

120 jumps x 5/jump = zz

there's a rectangle, a trapezoid, and a parallelagram. what group would u sort these into

750

vxdshfccfsethvfgxcdfzfgggggxczfsdxsdZZ xcdzdfhffdsasdxafgfdasfsfgdshd drrrrrrrrfggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

- 5th grade math -
**Anonymous**, Monday, April 22, 2013 at 10:58amfreaky frog at 750

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