Posted by **Lori** on Monday, September 25, 2006 at 8:01pm.

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9. km/h due east. Runner B is initially 5.0 km east of the flagpole and is running with a constant velocity of 8.0 km/h due west. How far are the runners from the flagpole when their paths cross?

I did it this way.

time for A to get to the flag pole is t = d/r = 6/9 = 0.667 hour.

time for B to get to the flag pole is t = d/r = 5/8 = 0.625 hour.

That means runner B gets to the flag pole first and will still be running west BEFORE runner A gets to the flag pole. Thus, runner B will run the 5 km + a distance x and runner A will run 6 - x. Setting that up.

Runner A. t = (6-x)/9

Runner B. t = (5+x)/8.

Now set the times equal and solve for x.

(6-x)/9 = (5+x)/8

Their paths will cross at 6 km - x km and 5 km + x km.

x is the distance from the flag pole when their paths cross.

I hope this helps.

- Physics -
**vv**, Monday, August 27, 2012 at 9:39pm
is it 0.176

- Physics -
**mariana**, Friday, November 2, 2012 at 7:10pm
i dont know

- Physics -
**Rain**, Friday, August 30, 2013 at 5:47am
yes, it is

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