Monday
March 30, 2015

Homework Help: physics

Posted by fluffy on Saturday, September 23, 2006 at 2:46am.

A 1200.0kg car is moving east at 30.0 m/s and collides with a 3600.0 kg truck moving at 20 m/s in a direction 60 degrees north of east.The vehicles interlock and move off together.Find their common velocity.


Use the law of conservation of momentum. The resultant momentum of the two cars before collision equals the final momentum of the interlocked vehicles, which have a combined mass of 4800 kg.

If +y is north and +x is the east direction, the initial momentum has components
Px = (1200 * 30) + (3600 * 20 cos 60)
and
Py = 3600 * 20 sin 60

If Vx and Vy are the velocity componensts of the interlocked vehicles,
4800 Vx = Px
4800 Vy = Py

Solve for Vx and V

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics - A 1500-kg car moving north at 27.0 m/s is struck by a 2165-kg car ...
physics - A 2,000-kg car moving east at 10.0 m/s collides with a 3,000-kg car ...
Physics D - A 1500-kg car moving north at 27.0 m/s is struck by a 2165-kg car ...
AP Physics B - A 2189 kg car moving east at 9.73 m/s collides with a 3285 kg car...
physics - a 2191 kg car moving east at 9.9 m/s collides with a 3221 kg car ...
physics - a 2191 kg car moving east at 9.9 m/s collides with a 3221 kg car ...
Physics - A 2170 kg car moving east at 10.5 m/s collides with a 3230 kg car ...
physics - A 1300-kg car moving north at 27.0 m/s is struck by a 2165-kg car ...
Physics - A 1300-kg car moving north at 27.0 m/s is struck by a 2165-kg car ...
Physics - A 1365-kg car moving north at 27.0 m/s is struck by a 2165-kg car ...

Members