Posted by **Haley** on Thursday, September 21, 2006 at 10:42pm.

Tell me how to figure out these probabilities

In how many different orders can 9 people stand in line?

In how many ways can 4 people be seated in a row of 12 chairs?

Thank you

For the first problem, we have nine people and want to arrange them in a line. For the first position there are 9 choices, for the second position 8, the third 7, etc. on down to 2 and 1. Thus there are

9*8*7*...*2*1 ways to arrange 9 people in a line.

For the second problem, the first person has 12 choices to be seated, the second has 11, the third 10 and the fourth 9. Another way to think of the problem is to ask how many ways could we select 8 empty chairs from the 12? Of the 4 chairs that were not selected, there are 4! ways to seat the people, thus the number would be

4! times 12 choose 8 = 4!*(12!/(4!8!)). Verify that both methods are equivalent.

9 people can stand in line 81 ways-I think-I'm not sure though

And i dont know the answer to the second one. My answer is alot

Emily, I know that I am responding very late, but I do not think that 81 is the answer...I know that it is way more than 100

## Answer this Question

## Related Questions

- algebra - Six people are going to be seated in a row of 8 chairs. How many ...
- algebra - six people are going to be seated in a row of 8 chairs. how many ...
- algebra - Six people are going to be seated in a row of 8 chairs. How many ...
- math - Six people are going to be seted in a row of 8 chairs. How many different...
- math - one third of the people in a convention room are seated in three-fourths ...
- math - in how many ways cn 4 people be seated around a circular table with 4 ...
- Math Repost - There are 5 boys and 4 girls in my class. In how many ways can ...
- math - There are 5 boys and 4 girls in my class. In how many ways can they be ...
- math - how many ways can a,b,c,d be seated in a row of 4 chairs (no repeats)
- Math - 8 people are going to sit on 6 chairs. Two of them John and Kelly can't ...