Another student determined the concentration of a vinegar solution to be 0.240 mol/L. If the accepted value for the concentration of the vinegar is 0.250 mol/L, the student's percentage erreo is

A. 1.00%
B. 1.24%
C. 2.40 %
D. 4.00%

b. of corse

See correct answer above.

To determine the student's percentage error in this case, we need to calculate the absolute difference between the student's determined concentration and the accepted value, and then express it as a percentage of the accepted value.

The absolute difference can be calculated as:

Absolute Difference = |Student's determined concentration - Accepted value|

= |0.240 mol/L - 0.250 mol/L|

= |-0.010 mol/L|

= 0.010 mol/L

Now, to express this as a percentage of the accepted value:

Percentage Error = (Absolute Difference / Accepted value) * 100

= (0.010 mol/L / 0.250 mol/L) * 100

= 0.04 * 100

= 4.00%

Thus, the student's percentage error is 4.00%. Therefore, the correct answer is D. 4.00%.