What is the balanced net ionic equation for the reaction of dilute nitric acid with solid aluminum oxide?

Frankly, I thought aluminum oxide was insoluble in almost anything except alkali. My CRC Handbook lists it soluble in alkali and organic solvents. The Merck Index lists it insoluble in acids at elevated temperature but doesn't say anything about solubility at room temperature. However, IF it is soluble, this will be the molecular equation. And I don' think it is a redox equation.

HNO3(aq) + Al2O3(s) ==> Al(NO3)3(aq) + H2O(l)
1. Balance the equation first. If you have trouble, repost and tell me what your problem is as succintly as possible. aq stands for aqueous, s for solid, and l for liquid. Those letters simply show the state of each molecule.

2. Change the aq materials into ions on both sides. Retain the others as molecules.

3. Cancel any ions that are common to both sides.

4. The result will be the net ionic equation.

I shall be happy to check your work.

To find the balanced net ionic equation for the reaction of dilute nitric acid with solid aluminum oxide, follow these steps:

1. Start with the given molecular equation:
HNO3(aq) + Al2O3(s) --> Al(NO3)3(aq) + H2O(l)

2. Convert the aqueous substances (HNO3 and Al(NO3)3) into ions. In this case, nitric acid (HNO3) dissociates into H+ and NO3- ions, while aluminum nitrate (Al(NO3)3) dissociates into Al3+ and NO3- ions. The solid aluminum oxide (Al2O3) does not dissociate and remains unchanged.

H+ + NO3- + Al2O3(s) --> Al3+ + NO3- + H2O(l)

3. Cancel out the common ions on both sides of the equation. In this case, the NO3- ions appear on both sides and can be eliminated.

H+ + Al2O3(s) --> Al3+ + H2O(l)

4. The resulting equation is the net ionic equation:
H+ + Al2O3(s) --> Al3+ + H2O(l)

This balanced net ionic equation represents the reaction of dilute nitric acid with solid aluminum oxide.