The KHP used in the titration with NaOH was contaminated with sodium hydrogen phyhalate (NaHC8H4O4), but you didn't know it. State the effect of the final result (falsely high, falsely low, or unaffected) Explain.
thanks
These problems must be reasoned through.
(1)mols KHP = mols NaOH
(2)mols KHP = mass KHP/molar mass
(3)Molarity NaOH = mols NaOH/mL NaOH
If KHP was contaminated with NaHP:
NaOH will titrate just as much H as if we had pure KHP. The molar mass of NaHP is less than that of KHP. Therefore, we weigh out KHP but it weighs less than if it were pure, which makes the mols KHP less (equation 2) and smaller mols in equation (3) makes the molarity ??. Or we can go another route. We weigh KHP, dividing by molar mass KHP in equation (2) when we should be dividing by a smaller "average" molar mass (since Na has a smaller atomic mass than K) produces fewer mols in (2) and that has ?? effect on the molarity in equation (3). I hope this helps. I find just putting each equation we use in the titration helps (even for percent problems), then start at the top and work through each equation until you get to the last one. In this case the last one was molarity of NaOH, but it could be carried further and ask for the effect on percent of an unknown acid. Then we just plug "a smaller number for molarity" into the percent equation and we have the effect on percent of the acid.
What is the H when you said "the NaOH will titrate just as much H as if we had pure KHP?"
Thanks for your help.
In the statement "the NaOH will titrate just as much H as if we had pure KHP," H refers to hydrogen atoms.
During the titration, the NaOH reacts with the KHP molecule by transferring hydrogen ions (H+) from the KHP to the NaOH. This reaction is based on the principle of acid-base neutralization, where a strong base (NaOH) reacts with a strong acid (KHP) to produce a salt.
In this context, H represents the hydrogen ions that are being transferred from the KHP molecule to the NaOH molecule during the titration process. The presence of sodium hydrogen phthalate (NaHC8H4O4) in the KHP does not affect the amount of hydrogen transferred during the reaction. Hence, the statement implies that the titration will still accurately measure the amount of hydrogen ions present in the solution, just as it would if the KHP were pure.