Friday
April 18, 2014

Homework Help: Science

Posted by Christina on Tuesday, September 19, 2006 at 6:09pm.

A particle has a velocity of 18m/s at a certain time and 2.4s later is velocity is 30m/s in the opposite direction. What are the magnitude and direction of the particle's acceleration during the 2.4s interval?

I udes a=change in velocity /change in time and I got -20m/s^2 is this correct?


If we use
(v_f - v_o)/t = a where v_f=-30m/s, v_o=18m/s and t=2.4s then
a = (-30-18)/2.4 m/s^2
So yes, it looks correct to me.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

science - A particle had a speed of 18m/s at a certain time and 2.4 s laer its ...
Physics - At a certain time a particle had a speed of 17 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 17 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 16 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 16 m/s in the positive x ...
Physics - As a baseball is being caught, its speed goes from 27.5 m/s to 0.0 m/s...
Please help me with M1 kinematics! - A particle is travelling with velocity (4i...
science - a particle is moving with a velocity of 5m/s .after 5sec it is found ...
Physics - At a certain time a particle had a speed of 60 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 60 m/s in the positive x ...

Search
Members