Tuesday

March 31, 2015

March 31, 2015

Posted by **Morgan** on Tuesday, September 19, 2006 at 4:47pm.

In how many seconds after being thrown does the rock strike the ground?

What is the speed of the rock just before it strikes the ground?

The position of the rock is

s = (-1/2)g*t^2 + (12m/s)*t + 40

Use the quadratic formula to find t when s = 0

The speed is |-g*t + 12| those are absolute value bars and the t from the first part.

Check my set-up for this.

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