Posted by **Lindsay** on Monday, September 18, 2006 at 2:20pm.

Given that the distancef rom Earth to the Moon is 3.8 x 10^8 m, that the Moon takes 27 days to orbit Earth, and that the mass of the Moon is 7.4 x 10^22 kg, what is the acceleration of the Moon and the size of the attractive force between Earth and Moon?

Use v = (2pir)/T, where r is the radius of orbit (the distance between the 2), and T is the time for one orbit. pi, is, of course, pi....3.14159...

Once you know velocity, you can get the centripetal acceleraion by a = v^2/r, and F (the force) = mv^2/r

- physics -
**Anonymous**, Tuesday, January 5, 2016 at 12:42pm
Dheje

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