Homework Help: physics

Posted by Lindsay on Monday, September 18, 2006 at 2:20pm.

Given that the distancef rom Earth to the Moon is 3.8 x 10^8 m, that the Moon takes 27 days to orbit Earth, and that the mass of the Moon is 7.4 x 10^22 kg, what is the acceleration of the Moon and the size of the attractive force between Earth and Moon?

Use v = (2pir)/T, where r is the radius of orbit (the distance between the 2), and T is the time for one orbit. pi, is, of course, pi....3.14159...
Once you know velocity, you can get the centripetal acceleraion by a = v^2/r, and F (the force) = mv^2/r

No one has answered this question yet.

Answer this Question

Related Questions

physics - The physics of energy and Earth's moon as a satellite. The moon is...
physics - Moon is a natural satellite of the Earth, circling it with period (...
physics - given that the radius of the earth is 6.37×10^3km and the period...
Physics - What is the centripetal acceleration of the Moon? The period of the ...
Physics - What is the centripetal acceleration of the Moon? The period of the ...
physics - the moon orbits the earth in a circle (near enough) of radious 3.8x10^...
physics - Given that the Moon's period about the Earth is 27.32 days and the...
science - The pull of gravity keeps the Moon in orbit around Earth. The distance...
physics - The moon is receding from the Earth by approximately 3.8 cm per year. ...
Physics - A. Use the relation 2 m m m GM g R ƒ to find the ...

For Further Reading

First Name:
School Subject:
Answer: