Saturday

October 25, 2014

October 25, 2014

Posted by **Please help this time?? Becca** on Sunday, September 17, 2006 at 10:22pm.

I'm not sure how I'm supposed to set up the equation. I know avg v= delta x over delta t, but I can't get it so that it works.

The average V while accelerating and decelerating is half the uniform velocity between B and C. If all three distances are equal, it will therefore take twice as long to do AB or CD as it will to travel BC. That means 2/5 of the time is spent accelerating and decerlating, and 1/5 at constant velocity (BC).

You had the right equation in mind, but just needed to follow through with the logic.

**Answer this Question**

**Related Questions**

Physics - A train travels between stations 1 and 2. The engineer of the train is...

Physics - A train travels between stations 1 and 2. The engineer of the train is...

math - The diagram below shows the speed time graph for a train travelling ...

physics - (a) If the maximum acceleration that is tolerable for passengers in a ...

Physics - (a) If the maximum acceleration that is tolerable for passengers in a ...

physics - A train going from one station to the next on a straight section of ...

Physics - A light-rail train going from one station to the next on a straight ...

Physics - A subway train is designed with a maximum acceleration of ±0.637 m/s2...

PHYSICS help!!!!!! - A commuter train travels between two downtown stations. ...

Math - Train A and train B leave station going in opposite directions. Train B ...