Saturday

February 28, 2015

February 28, 2015

Posted by **jenny** on Sunday, September 17, 2006 at 4:28pm.

Calculate a) the speed v and b) the max height reached by the stone above point B.

I can't find the equation

You need to derive the solution in problems such as this. You can do that by "thinking it through", using equations you should already know. There are many ways to solve the problem. I will choose energy.

In going from point A to point B, the potential energy increases by M g H, there h = 3 m and g = 9.8 m/s^2.

The change (increase) in potential anergy will equal the decrease in kinetic energy. Therefore

M g H = (1/2) M [v^2 - (v/2)^2]

2 g H = (3/4) v^2

Solve that for v. You can use conservation of energy again to solve for the maximum height attained. That would occur when the potential energy increase equals the initial kinetic energy.

**Answer this Question**

**Related Questions**

physics - A stone is thrown vertically upward. On its way up it passes point A ...

Physics 4a - A stone is thrown vertically upward. On its way up it passes point ...

physics - A stone is thrown vertically upward. On its way up it passes point A ...

Physics - A stone is thrown vertically upward. On its way up it passes point A ...

Physics - A stone is thrown vertically upward. On its way up it passes point A ...

Physics - A stone is thrown vertically upward. On its way up it passes point A ...

physics - A stone is thrown vertically upward with a speed of 15m/s.what is the ...

physics - A ball is thrown vertically upward with an initial speed of 20 m/s. ...

physics - ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...

physics - ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...