Tuesday

September 2, 2014

September 2, 2014

Posted by **sara** on Sunday, September 17, 2006 at 2:44pm.

a) What is the initial speed of the second stone?

Write an equation for the vertical height of each stone. Let t=0 be the time the first stone is dropped. The second stone must have an initial vertical (downward) velocity so it can catch up with the first.

Y1 = 43.9 - (g/2) t^2

Y2 = 43.9 - Vo (t-1) - (g/2)(t-1)^2

Set Y1 = 0 and Y2 = 0 (the heights when each hit the ground). Use the first equation to solve for t. Use the second equation to solve for Vo, the initial downward velocity of the second stone. Note that t-1 is the time of flight of the second stone.

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