Posted by
**puff puff** on
.

An airplane flies at airspeed (relative to the air) of 400km/h. The pilot wishes to fly due North (relative to the ground) but there is a 110km/h wind blowing Southwest (direction 225ยบ clockwise from North). In what direction should the pilot head the plane (measured clockwise from North)? Answer in Units of degrees. COuld anyone help me on this question? I'm stuck. thanks a lot!

The component of the wind blowing west needs to be determined. Determine that value (XXX)

Then, the Easterly component of the pilots velocity vector must cancel that, or SinTheta=XXX/400 Where theta is the angle E of N.

check my thinking.

how do i calculate the component of the wind blowing west? is it like:

sin(45) x 110km/h = 77.78km/h ? thanks again!

Yes. That is correct.

thank so much!!