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November 26, 2014

November 26, 2014

Posted by **Chris** on Saturday, September 16, 2006 at 8:50pm.

b) 81.5 (+/- 0.5) x 40.2 (+/- 0.2)/ 21.8 (+/- 0.2)

my answer for absolute error was 150. +/- 200, which is outrageous. Can someone show how they would do it so I can compare and find my mistake?

error/(81.5* 40.2/ 21.8)=.5/81.5 +0.2/40.2 + .2/21.8

absolute error = about 3, so the percent error would be 3/(81.5* 40.2/ 21.8) *100 or 300/150 about 2 percent.

check you work.

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