Is the given number a solution of the equation or the inequality?

4y-7=3y-4;3

equation

I think it is the inequality.

Try substituting 3 for y and see what you get.
4*3-7=3*3-4 or 12-7=9-4
Is this a valid equality?
Alternative solution: solve for y
4y-7=3y-4 so
y=3 thus 3 is a solution for the equation.

yes! cuz 4(3)=12-7=5, so 3(3)=9-4=5 so they're both equal see im smart!!!

2 friends are 60 miles apart. They decide to thier bicycles to meet each other. Sally starts from the college and heads east, riding at a rate of 21 mph. At the same time Teresa starts from the river and heads west, riding at a rate of 15 mph. How far does each cyclist ride in t hours? When the cyclists meet, what must be true about the distances they have ridden? Write and solve an equation to find when they meet.

To find the distances each cyclist rides in t hours, we need to determine their respective distances based on their speeds and the time traveled.

Sally rides at a rate of 21 mph for t hours. Therefore, the distance she travels is given by d = 21t.

Teresa rides at a rate of 15 mph for t hours. Therefore, the distance she travels is given by d = 15t.

When the cyclists meet, the sum of their distances should be equal to the total distance between them, which is 60 miles.

So, we can set up the equation: 21t + 15t = 60.

Combining like terms, we get 36t = 60.

Now, solve for t by dividing both sides of the equation by 36: t = 60/36.

Simplifying further, t = 5/3 hours or approximately 1 hour and 40 minutes.

To find the distances each cyclist has ridden, substitute the value of t back into the distance formulas:

Sally: d = 21t = 21 * (5/3) = 35 miles.

Teresa: d = 15t = 15 * (5/3) = 25 miles.

Therefore, Sally travels 35 miles and Teresa travels 25 miles when they meet.

It is worth noting that the sum of the distances traveled by each cyclist is indeed 60 miles, as they meet at that point.