Wednesday

October 1, 2014

October 1, 2014

Posted by **Jennifer** on Thursday, September 14, 2006 at 3:44pm.

This problem wants you to use the formula

v = (-1/2)gt^2 + v_0

g=9.8m/s^2 and v_0 = 61m/s so

v = (-1/2)g*(1s)^2 + 61m/s at t = 1.

I wrote the formula wrong. It should be

v = -gt + v_0

I mixed the velocity formula and the distance formula.

You need the formula: velocity (finall) = velocity (initial) + at.

Here, the velocity initial is 61, and the t (time) is 1s. Remember, since the ball is decelerating (the acceleration is in the oppostie direction to which the ball is thrown), the a is -9.8m/s^2. Just plug 'em in!

**Answer this Question**

**Related Questions**

Physics - A ball is thrown horizontally from a platform so that the initial ...

Physics - A ball is thrown horizontally from a platform so that the initial ...

Physics - A red ball is thrown down with an initial speed of 1.3 m/s from a ...

physics - A red ball is thrown down with an initial speed of 1.2 m/s from a ...

Physics - A red ball is thrown down with an initial speed of 1.2 m/s from a ...

Physics - A ball is thrown straight upward and returns to the thrower's hand ...

physics - A ball is thrown straight upward and returns to the thrower's hand ...

Physics - A ball is thrown straight upward and returns to the thrower's hand ...

Physics - if a ball is thrown straight upward and is caught 5s after being ...

college - A blue ball is thrown upward with an initial speed of 19.8 m/s, from ...