Homework Help: math

Posted by Rob on Wednesday, September 13, 2006 at 8:56pm.

Determine whether there are 2 consecutive odd integers such that 5 times the first exceeds three times the second by 54.
Can anyone help???

We're asked:
Determine whether there are 2 consecutive odd integers such that 5 times the first exceeds three times the second by 54.
Let the first odd number be 2k+1, then the next odd number is is 2(k+1)+1=2k+3.
Then 5*(2k+1)=3*(2k+3)+54 so
10k+5=6k+9+54 thus
4k=58
Since 4 does not divide 58 there is no k to satisfy the integers, so the answer is no, the integers don't exist.
The closest k's we could use are 14 and 15.
Consider k=14, then 2k+1=29 and 2k+3=31
We find 5*29=145, 3*31=93 and 145-93=52
Consider k=15, then 2k+1=31 and 2k+3=33
We find 5*31=155, 3*33=99 and 155-99=56
Check that the problem was entered correctly and that I read it correctly.

Since 5x = 3(x + 2) + =54, 2x = 60 making x = 30 and (x + 2) = 32.

I guess not.

No one has answered this question yet.

Answer this Question

Related Questions

Pre-Algebra - Find two consecutive odd integers such that 5 times the first ...
math - Find three consecutive odd integers such that twice the sum of the first ...
algebra - Find the two consecutive odd integers such that 5 times the first ...
algebra - I have been working this one for awhile and have become more confused...
Algebra II - Find 4 consecutive odd integers such that 5 times the sum of the ...
Math - Find three consecutive integers such that 5 times the first and third is ...
algebra - If the first and third of three consecutive odd integers are added, ...
math - find 3 consecutive odd integers such that the product of the first and ...
maths - 1. If the first and third of three consecutive odd integers are added, ...
algebra - Find four consecutive odd integers so that five times the sum of the ...

For Further Reading

First Name:
School Subject:
Answer: