Saturday

August 30, 2014

August 30, 2014

Posted by **joe** on Tuesday, September 12, 2006 at 9:34pm.

I answered this question this morning. Check the page previous to this. Let me know if you have questions about it. The post should be near the bottom of the thread begun by jack.

i do not understand the last part with the S~8 = 6S~6 - 5S~4 + 62.

Ok, that does require a little calculating -and observation.

If you take the poly

x^4+px^3+qx^2+rx+s with roots a,b,c,d and multiply it by x^4-px^3+qx^2-rx+s you get a poly whose terms are x^8,x^6,x^4,x^2,x^0(constant term) and the roots are a^2,b^2,c^2,d^2

The coefficient of the x^6 term is s-2.

If you make the sub. y=x^2 you get a poly y^4+p1y^3+p2y^2+p3y+p4. If you repeat this proces that we did above, i.e. negate the coefficients of the odd power terms and multiply them you get a poly whose terms are y^8,,,y^0 all even numbers. The coefficient of the y^6 term is S-4. If you do the process once more you get S-8.

To evaluate that expression the questioner is asking you to calculate S-4, S-6 and S-8 and verify they satisfy that equation, that's all.

To calculat S-6 I observed that in the first y polynomial the coefficient of y^3 is -s1, of y^2 is s2 and of y is -s3 and that (s1)^3-3s1s2+3s3=S-2 where the lower case s's are the symmetric functions. I'm not sure if you've been asked to calculate that or not. Let me know if this explains matters.

I just noticed a couple typos here. This line;

"To calculat S-6 I observed that in the first y polynomial the coefficient of y^3 is -s1, of y^2 is s2 and of y is -s3 and that (s1)^3-3s1s2+3s3=S-2 "

That should be S-6 not S-2 at the end. The other typos are minor.

i understand better now, thanks

You're welcome, feel free to post if anything's not clear. I should mention that this would be a fairly challenging problem for college students. Nice job doing this here.

**Related Questions**

math - The roots of the eqn x^4 - 3x^2 + 5x - 2 = 0 are a, b, c, d, and a^n + b^...

further mathematics - The roots of the eqn, x^4 + px^3 + qx^2 + rx + s = 0 where...

Math - Roots Ok, what about roots? Roots of polynomials? Square roots? Cube ...

algebra 1,urgent - the expression (4x^2-3x+1)-(x^3+2x+7) what is the coefficient...

Math - LOL I can't figure this out. It should be easy it's been years since I've...

Math - How to factor x^3 - 3x^2 + 4 =0 Use D'Alembert's Rational Roots Theorem. ...

Algebra 1 - 1.To solve the linear system below, which substitution of unkowns is...

Precalculus - "Show that x^6 - 7x^3 - 8 = 0 has a quadratic form. Then find the ...

Math - A math teacher wrote x^2+bx+c=0 on the board and asked students to find ...

Algebra 1 - 1. How many solutions does the linear system have ? 3x - y = 4 -3x...