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July 4, 2015

Homework Help: another algebra word problem

Posted by nicole on Tuesday, September 12, 2006 at 8:31pm.

okay guys, just one more word problem. and i don't think this one has any typos in it:

The perimeter of a rectangle is 27 cm and its area is 35 square centimeters. Find the length and the wide of the rectangle.

i just need help getting it started...


Ok P=27cm where P is the perimeter. A = 35cm^2 where A is the area.
We know that A =L*W and P=2(L+W) thus we have
(1) 35=L*W
(2) 27=2(L+W)
From (1) we have 35/L = W. Use this in (2) to get
27=2(L + 35/L) Now solve for L. This is a quadratic equation.


thanks a lot. i had been trying to do this for a long time :)


Velocity of 10 meters per second from the top of a 24 meter high cliff and it misses the cliff on the way down when will the rock be 4 meters from the water below?


y=x2-10x

# people have a combined height of 10 ft. 9 inches. A is 9 inches shorter than B, who is 6 inches taller than C. How talle are A,B, and C?

3 people have a combined height of 10 ft. 9 inches. A is 9 inches shorter than B, who is 6 inches taller than C. How talle are A,B, and C?

y=x(x-10)
x=0
x-10=0

solutions=0 and 10

rjty

The hypotenuse or a right angle has a length of 13 cm. The sum of the lengths of the other two sides is 17. Find the unknown side lengths.

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