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A ball is throen vertically downward from the rop of a 36.6 m tall building . The ball passes the top of a window that is 12.2 m above the groung 2.00s after being thrown. What is the speed of the ball as it passes the top of the window?

Would i need to use this equation
v= v0 +at?

We don't know the velocity it was thrown with nor the velocity when it reaches the window so we wouldn't use that formula
We would use s=(-1/2)g*t^2 + v_0*t + 36.6
At t=2sec s=36.6m-12.2m=24.4m find v_o.

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