At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constant acceleration of 2.50 m/s^2. At the same instant, a truck, traveling with a constant speed of 15.4 m/s, overtakes and passes the automobile.

How far beyond its starting point does the automobile overtake the truck?
GOT THIS!!!! 190 m

How fast is the automobile traveling when it overtakes the truck?
Don't know this part....

v=at
a=2.5m/s^2 how long is it until v=15.4m/s?
Now s=(1/2)at^2
Use the value you found for t in this formula to find the distance.
You could also multiply it by the truck's constant speed to find how far it traveled during that time.
The auto's speed is given by the first equation above. Use the given acceleration and time you found to find v. Please post your work too.

I think I got this wrong
We have s=(1/2)at^2 and s=vt for the car and truck respectively. Thus
(1/2)at^2 = vt or 2v/a=t so your 190m looks correct when we use v=15.4m/s and a=2.50m/s^2

1675 4

To solve for the time it takes for the car to reach the speed of 15.4 m/s, we can use the formula v = at, where v is the final velocity, a is the acceleration, and t is the time. Rearranging the equation, we get t = v/a.

Plugging in the values, we have t = 15.4 m/s / 2.50 m/s^2 = 6.16 seconds.

Now, to find how far beyond its starting point the automobile overtakes the truck, we can use the kinematic equation s = (1/2)at^2, where s is the distance, a is the acceleration, and t is the time. Plugging in the values, we have:

s = (1/2)(2.50 m/s^2)(6.16 s)^2 = 95.13 meters.

Therefore, the automobile overtakes the truck at a distance of approximately 95.13 meters beyond its starting point.

To determine the speed of the automobile when it overtakes the truck, we can use the equation v = at. Plugging in the values, we have:

v = (2.50 m/s^2)(6.16 s) ≈ 15.40 m/s.

So, the speed of the automobile when it overtakes the truck is approximately 15.40 m/s.