Write out the net ionic equation for:
Cd(NO3)2 + Na2S -----> 2NaNO3 + CdS
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thanks!!
Write out the net ionic equation for:
Cd(NO3)2 + Na2S -----> 2NaNO3 + CdS
If this is done in a water solution, then the sodium nitrate will be in solution, as was the Cd(NO3)3 (both are soluble. So the sodium and nitrate ions are not in the reaction...
Cd++ + S-- >> CdS is the net ionic equation.
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You're welcome! If you have any more questions, feel free to ask.
To write out the net ionic equation for the given reaction, you need to first identify which compounds are soluble and which ones form precipitates. In this case, Cd(NO3)2 and Na2S are both soluble in water, so they will dissociate into their respective ions.
The dissociation of Cd(NO3)2 yields Cd2+ and 2NO3- ions:
Cd(NO3)2 → Cd2+ + 2NO3-
The dissociation of Na2S yields 2Na+ and S2- ions:
Na2S → 2Na+ + S2-
Now, we can write out the complete ionic equation by combining the ions involved in the reaction:
Cd2+ + 2NO3- + 2Na+ + S2- → 2Na+ + 2NO3- + CdS
Since the sodium (Na+) and nitrate (NO3-) ions are present on both sides of the equation and don't participate in the reaction, they are considered spectator ions. Therefore, we can eliminate them from the equation, resulting in the net ionic equation:
Cd2+ + S2- → CdS
This shows that the Cd2+ ion reacts with the S2- ion to form CdS, which is the precipitate in this reaction.