What is the width of a rectangle with a perimeter of 70 feet if its length is 1 foot? 2 feet? L.feet?

perimeter = 2(length + width)
If perimeter = 70 then 35= length + width
Now substitute 1,2,and L and solve for width.

how do you find the L. feet?

L is supposed to be any length L
Perimeter/2 = L + width so
perimeter/2 - L = width
Here 35 - L = width

To find the width of the rectangle with a given length L and a perimeter of 70 feet, you can use the formula for the perimeter of a rectangle, which is perimeter = 2(length + width).

First, substitute the given perimeter of 70 feet into the formula:
70 = 2(length + width)

Next, to find the width when the length is 1 foot, substitute the given length of 1 foot into the equation:
70 = 2(1 + width)

Simplify the equation:
70 = 2 + 2width

Subtract 2 from both sides:
70 - 2 = 2width
68 = 2width

Divide both sides by 2:
34 = width

Therefore, when the length is 1 foot, the width of the rectangle with a perimeter of 70 feet is 34 feet.

To find the width when the length is 2 feet, substitute the given length of 2 feet into the equation:
70 = 2(2 + width)

Simplify the equation:
70 = 4 + 2width

Subtract 4 from both sides:
70 - 4 = 2width
66 = 2width

Divide both sides by 2:
33 = width

Therefore, when the length is 2 feet, the width of the rectangle with a perimeter of 70 feet is 33 feet.

To find the width when the length is L feet (where L can be any length), substitute the value of L into the equation:
70 = 2(L + width)

Simplify the equation:
70 = 2L + 2width

Subtract 2L from both sides:
70 - 2L = 2width

Now, to find the width, divide both sides by 2:
35 - L = width

Therefore, when the length is L feet, the width of the rectangle with a perimeter of 70 feet is (35 - L) feet.