At a construction site a pipe wrench struck the ground wiht a speed of 24 m/s.

a) From what height was it inadvertently fropped?

b) How long was it falling?

for a) the book said it was 29.4m and for b) it was 2.4s but I keep on getting the wrong answers.

s=(1/2)gt^2
v=g*t
g=9.8m/s^2
v=24m/s so t=(24m/s)/(9.8m/s^2)
Use that in the first equation and you should get the book's answers.

rounding issues

jiowejafw

To find the height from which the pipe wrench was dropped, we can use the equation s = (1/2)gt^2, where s is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of falling.

Given that the initial velocity is 24 m/s, we can find the time of falling using the equation v = gt. Rearranging the equation, we have t = v/g.

Substituting the given values, we can find the time:
t = (24 m/s) / (9.8 m/s^2) ≈ 2.45 s

Now, we can use this time to find the height:
s = (1/2) * (9.8 m/s^2) * (2.45 s)^2 ≈ 29.4 m

Therefore, the height from which the pipe wrench was inadvertently dropped is approximately 29.4 meters.

For part b) - the time it takes for the wrench to fall - we have already calculated it as approximately 2.45 seconds. However, the book states the answer as 2.4 seconds. This could be due to rounding differences.

Using the equations and calculations provided, you should be able to arrive at the correct answers of 29.4 meters and approximately 2.45 seconds.