Tuesday

September 30, 2014

September 30, 2014

Posted by **Josh** on Wednesday, August 30, 2006 at 6:58pm.

a- Cos thata

b- tan squre of thata

c csc (90 degree - thata)

d- sin squre thata

secTheta=3

but secTheta= 1/cosTheta

solve for cosTheta

Then, sin^2theta+ cos^2Theta=1

solve for sinTheta.

then, Tan theta= sinTheta/cosTheta

you have it.

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