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December 22, 2014

December 22, 2014

Posted by **jenny** on Tuesday, August 29, 2006 at 11:53pm.

Looks like a pretty fun problem to me. What have you tried so far?

Ok, well let's try to formulate this into a system of 2 equations in 2 unknowns.

Let x denote the number of peanuts with 2 inside and y the number with 3 inside.

Then we know that x+y=the number of peanuts = 35

We also know that 2*(peanuts with 2 inside) + 3*(peanuts with 3 inside) = total peanuts = 78 Thus our system is

x + y = 35

2x + 3y = 78

Now add -2 times the first equation to the second to get

-2x + 2x + -2y + 3y = -2*35 + 78 or

y = 8

You should be able to finish and verify the solution for the number of double shells.

Did you follow all the steps I did?

Let X = # double shells.

and Y = # triple shells.

========================

You have two equations and two unknowns.

X + Y = 35 (total shells)

2X + 3Y = 78 (total peanuts)

Solve for X and Y. I hope this helps. Post your work if you get stuck and require more assistance.

Thanks for your help!

will you help my with math

Select the Post a New Question link above and present your question. We'll try to help.

- math -
**confuzzled**, Monday, May 16, 2011 at 5:47pmhelp!

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