Posted by **Tiff** on Thursday, August 24, 2006 at 9:35pm.

On a mass of 100 kg, a force of 120 N acts right and at an angle of 30 degrees to the horizontal. If the coefficient of sliding friction is .1 what is the acceleration of the mass?

100N* cos30 -(100sin30+mg)(.1)= m*acceleration

[86.6025- [(-50 + (100)(-9.8)](.1)]/100

[86.6025- (-48)]/100

and so I got 1.346 as the answer.

Is this correct?

The force is 120N, not 100. I should have caught that earlier. Otherwise, it looks good.

**100N*** cos30 -(

**100N**sin30+mg)(.1)= m*acceleration

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