Posted by **fiaie** on Thursday, August 24, 2006 at 1:39pm.

In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles

In a triangle ABC, angle A is 2 times angles C and angle B is 20 degrees less than angle C find the number of degrees in these angles

A = 2C

B = C - 20

Since the sum of the degrees of any triangle

*always* = 180 degrees, A + B + C = 180. Substituting the above values of C for A and B will give you the value of C. Substitute the value of C in the other formulas and then check by putting all three values in A + B + C = 180.

I hope this helps. Thanks for asking.

um i am still confuse.. that helps alittle i did the problem and C= 50 do u plug that answer in the equation? i needa find the number of degrees in these angles...

** 50 degrees is correct for angle C.
**

You know A = 2C; therefore, A = 2 x 50 = 100.

You know B = C - 20. I will let you finish. I hope this helps. Check to make sure all of them add to 180.

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