Thursday

August 21, 2014

August 21, 2014

Posted by **cassii** on Tuesday, August 8, 2006 at 1:06pm.

expand:

x^-2 (y^2 + 10x)

z^3 (5x + 3z^-4)

First one:

x^-2 (y^2 + 10x)

x^-2 is the same thing as 1/x^2.

Therefore, we have this:

1/x^2 (y^2 + 10x)

Multiply using the distributive property:

y^2/x^2 + 10x/x^2

Add together because you have the same denominator:

(y^2 + 10x)/x^2

And that's as far as we can go on this one!

I'll let you try the second one on your own. Hint: z^-4 is the same as 1/z^4.

I hope this helps.

One other thing about your first problem; if you are to expand and leave it as y^2/x^2 + 10x/x^2, then reduce the second fraction and you will end up with this:

y^2/x^2 + 10/x

I hope this helps.

that was all one problem the stuff on the top has a line between the top and the bottom

Ok, let's approach the problem differently. Since this is all one problem, I'll rewrite it as such:

[x^-2 (y^2 + 10x)] /

[z^3 (5x + 3z^-4)]

Working it out:

[(y^2 + 10x)/x^2] /

[z^3(5x + 3/z^4)] =

[(y^2 + 10x)/x^2] /

[(5xz^3 + 3/z) =

[(y^2 + 10x)/x^2] /

[(5xz^4/z + 3/z)] =

[(y^2 + 10x)/x^2] /

[(5xz^4 + 3)/z] =

[z(y^2 + 10x)] /

[x^2(5xz^4 + 3)] =

(y^2z + 10xz) /

(5x^3z^4 + 3x^2)

This is as far as you can go; I don't see any other way to reduce this further.

**Related Questions**

how about his one - -7+ 5x = 10x-2? im not sure I know its -1, but im not sure ...

Math - Find the equation of the tangent line 5x^2+y^2=14 at (1,3). P.S: It's ...

algebra - Gina wrote this system of linear equations: 2x + y = 7 4x + 5y = 11 ...

math - 1. Gina wrote this system of linear equations: 2x + y = 7 4x + 5y = 11 ...

Pre-algebra - Solve. 29x – 2(9x – 0.455) = 10x + 0.525 Give us you thinking on ...

Algebra - almost done with Algebra...help! 2 3x – 6(2x – 0.055) = 10x + 0.515 I ...

math - f(x) = x^2 + 10x + 24 =(x^2 + 10x)+ 24 =(x^2 + 10x + 25 - 25) + 24 f(x...

Intermediate Algebra - Determine whether the point (1, 8) is a solution of the ...

math,factoring,help - Can someone please show me step by step how to do these. I...

Algebra I - Thanks Reiny, but I'm still lost. I understand how you multipled by ...