Posted by cassii on Tuesday, August 8, 2006 at 1:06pm.
i was wondering if anyone could help me on this problem.
expand:
x^-2 (y^2 + 10x)
z^3 (5x + 3z^-4)
First one:
x^-2 (y^2 + 10x)
x^-2 is the same thing as 1/x^2.
Therefore, we have this:
1/x^2 (y^2 + 10x)
Multiply using the distributive property:
y^2/x^2 + 10x/x^2
Add together because you have the same denominator:
(y^2 + 10x)/x^2
And that's as far as we can go on this one!
I'll let you try the second one on your own. Hint: z^-4 is the same as 1/z^4.
I hope this helps.
One other thing about your first problem; if you are to expand and leave it as y^2/x^2 + 10x/x^2, then reduce the second fraction and you will end up with this:
y^2/x^2 + 10/x
I hope this helps.
that was all one problem the stuff on the top has a line between the top and the bottom
Ok, let's approach the problem differently. Since this is all one problem, I'll rewrite it as such:
[x^-2 (y^2 + 10x)] /
[z^3 (5x + 3z^-4)]
Working it out:
[(y^2 + 10x)/x^2] /
[z^3(5x + 3/z^4)] =
[(y^2 + 10x)/x^2] /
[(5xz^3 + 3/z) =
[(y^2 + 10x)/x^2] /
[(5xz^4/z + 3/z)] =
[(y^2 + 10x)/x^2] /
[(5xz^4 + 3)/z] =
[z(y^2 + 10x)] /
[x^2(5xz^4 + 3)] =
(y^2z + 10xz) /
(5x^3z^4 + 3x^2)
This is as far as you can go; I don't see any other way to reduce this further.
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