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October 1, 2014

October 1, 2014

Posted by **jon** on Monday, July 31, 2006 at 12:40pm.

2.For the same data in problem number 1, show an alternate solution to the problem by finding the derivative of the trigonometric function, tan X for the given data. Show that the derivative of the tangent function will give the same angle found in the question 1. HINT: Angle measure must be done in radians.

Draw the picture.

The E distance component is 3/60*10 + 40Trunning. The N compoent is 5, the hypot is 40Trunning

Use the pyth theorm to get an equation, wit will be a quadratic , solve it for Trunning.

The N component is 5mi=40CosTheta*T, solve for Theta.

2. I dont understand this part. Theta is the firing angle, it is a constant, so the d/dt of tanTheta=0. Maybe the problem meant Theta as a function of something (initial range, carrier velocity, or torpedo velocity), but that is speculation. I am missing something here.

FYI, the best submarine torpedo in WWII was the 21inch Mk 17, it has a max speed of 33kts, and a max range of 13.5kyards. The torpedo cited above would have been a fantasy, as would have been a enemy carrier going only 10kts on a steady course. Life is not simple in war.

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