Posted by **kristie** on Wednesday, July 26, 2006 at 12:08pm.

can this equation be factored further?

y= x^4+2x^3+4x^2+8x+16

Not in the real number system. If you plot the function, you will see the minimum is at x=-1.1 (approx) and y is positive. At no x does the function equal zero, so there are no real roots, which means, no factors.

You can do some moving around..

x^4+2x^3+4x^2+8x+16

x^3(x + 2) + 4x(x + 2) + 16

(x+2)(x^3+ 4x) + 16

x(x +2)(x^2+4) + 16

I dont personally see that as progress.

Not having real roots doesn't mean it can't be factored: x^4+2x^2+1=(x^2+1)^2 has no real roots, but it does factor.

In theory every polynomial over R factors as polynomials of degree 1 or 2, but finding the factors can be time consuming in practice.

True.

## Answer this Question

## Related Questions

- Algebra II - 1)What method(s) would you choose to solve the equation: x2 + 2x - ...
- Pre-Calc/Trig - Please check the first and help with the second-thank you Find ...
- MATH,HELP - Can someone show me how to even do this problem. Find all positive ...
- Algebra - Find all positive values for k for which each of the following can be ...
- AlgebraB-2 - A model rocket is launched from a roof into a large field. The path...
- math - Which three options are true about the quadratic equation?? y= 4t^2 + 16t...
- algebra - Find all positive values for k for which each of the following can be ...
- Math - Real number system - Solve the following equation in the real number ...
- Physics - The Speed of train is reduced from 60km/h at the same time as it ...
- math - plot graph for y = 1.55x +30 and y= 2.75x where y (£)as a function of ...

More Related Questions