Posted by **kristie** on Monday, July 17, 2006 at 4:52pm.

the direction was to find f^(-1)x.

f(x) = x^2+2x+1, x >= -1

as a final answer, I got:

f^(-1)x = sqrt(x) - 1, x >= 0

is this right? I don't understand the restriction rules.

It is right. If originally x>=-1, that puts f(x) >=0, and in the inverse function, this restriction travels to the new domain.

kristie, Bob is correct. The restriction rule carries to f-inv.

In general, even funcions, those with a poly. whose degree is an even integer, must be restricted. They are not 1-1. 1-1 means that each horizontal line through f(x) intersects f in at most one point.

Note that restricting f here makes it 1-1, thus invertible.

## Answer this Question

## Related Questions

- inverse - find f^-1 (x). (this is asking me to find the inverse) f(x) = -(x-2)^2...
- Pre-calculus - Find the inverse function of f(x) = 4 - 8/x^2, where x>0 What ...
- Algebra 2 Honors - Hey, we recently started a topic in class that I don't ...
- math-Inverse functions - f(x)=-4x-2 & g(x)=5x-6. Find (f*g) and state domain. f(...
- Evaluation-repost - Reposting because it has gone down to the second page! ...
- Physics - Betty Bodycheck (mB = 55 kg, vB = 22.0 km/h in the positive x-...
- Physics - Betty Bodycheck (mB = 55 kg, vB = 22.0 km/h in the positive x-...
- calculus - f(x)=sqrt(x-2) what is the inverse of f? I got inverse f(x)= x^2+2 ...
- Calculus Verification - I just want to make sure im right. Find the derivative ...
- Algebra 2 - Find the geometric mean of each pair of numbers. 1/12, 1/18 I ...

More Related Questions