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November 27, 2014

November 27, 2014

Posted by **kristie** on Tuesday, July 11, 2006 at 10:04am.

ln(y-1)-ln2 = x +lnx

ln(y-1)-ln2 = x +lnx Solve for y...

ln[(y-1)/2]]=x + lnx

take the antilog of each side

(y-1)/2= e^(x+lnx)

solve for y.

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