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March 26, 2017

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how would you solve for y in this problem:

ln(y-1)-ln2 = x +lnx


ln(y-1)-ln2 = x +lnx Solve for y...
ln[(y-1)/2]]=x + lnx

take the antilog of each side
(y-1)/2= e^(x+lnx)
solve for y.

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