Tuesday

September 30, 2014

September 30, 2014

Posted by **kristie** on Tuesday, June 27, 2006 at 1:34pm.

x=(y^2+3y)^(1/3)

would it equal: y= x^3/y - 3 ?

and what about this problem:

x= 1/[(y^2+3y-5)^3]

would it equal: y = y/x + 5/y - 3?

I would appreciate your help very much!

<<how would you solve for y in this problem:

x=(y^2+3y)^(1/3)

would it equal: y= x^3/y - 3 ? >>

Your equation is correct but it does not allow you to solve explicitly for y. What you have to do is treat the "x-containing" term as if it were a constant in the quadratic equation:

y^2 + 3y -x^3 = 0

Then use the equation for the root of quadratic equations:

y = [-6 +/- sqrt (9 + 4x^3)]/2

The second question can be handled similarly.

**Answer this Question**

**Related Questions**

Algebra--Correction? - Solve x^2 -3x is greater than or equal to 10 Would the ...

integral confusion - integral of Sec[2x]Tan[2x] i know u is sec 2x du=...

Business Math - Using the simplex method, solve the following linear programming...

Physics. - 8. What happens when a wave reaches the boundary of a new media? A. ...

math - I am suppose to simplify the following problems: sqrt(x)/x (isn't that ...

i lied. very quick calc problem. - f(x) = abs(sin(x)), -pi less than or equal to...

Math Check - Solve the inequality. So i have done this problem at least three ...

Math - how do you solve this problem??? Write each rational number in the form a...

Algebra II - The inverse of f(x) is h(x). The composition of f and h is written ...

Pre Algebra - what would 6(1/3) be equal to? I'm currently doing Exponential ...