N2 + 3H2 --> 2NH3
how many grams of hydrogen are needed to react with 50 grams of nitrogen?
Three moles of H2 per one mole of N2. How many moles of N2 is 50 grams?
1.79 moles is 50 grams.
You do these problems in steps.
Step 1. Write a balanced chemical equation. You have that.
N2 + 3H2==> 2NH3
Step 2. Convert grams of what you have to mols remembering that mols = g/molar mass. mols N2 = 50/28 = 1.79.
Step 3. Convert mols of what you have (in this case N2) to mols of what you want (in this case H2) using the balanced equation from step 1. The coefficients do the trick if you make the units cancel.
mols H2 = 1.79 mols N2 x [3 mols H2/1 mol N2] = ?? mols H2.
Note that mols N2 cancel leaving you with mols H2 (and mols H2 is what you want)
.
Step 4. Now convert mols of what you want (from step 3) into grams using the formula from step 2 but in reverse; i.e., mols = g/molar mass and solving for g = mols x molar mass. You have mols and you use the molar mass of H2 which is 2.
g H2 = mols H2 x molar mass H2 = xx g H2 or, to watch the units;
g H2 = mols H2 x [2g H2/1 mol H2] = xx g H2.
Check my work. Check the numbers. I rounded to use whole numbers for molar masses. I hope this helps.
To determine how many grams of hydrogen are needed to react with 50 grams of nitrogen, you can follow these steps:
1. Write a balanced chemical equation: N2 + 3H2 --> 2NH3
2. Calculate the number of moles of nitrogen (N2) using the formula: moles = mass/molar mass.
The molar mass of N2 is 28 g/mol. Thus, moles of N2 = 50 g / 28 g/mol = 1.79 mol.
3. Use the balanced equation to find the number of moles of hydrogen (H2) required. According to the equation, there are 3 moles of H2 for every 1 mole of N2.
So, moles of H2 = 1.79 mol N2 x (3 mol H2/1 mol N2) = 5.37 mol H2.
4. Finally, calculate the mass of hydrogen (H2) using the formula: mass = moles x molar mass.
The molar mass of H2 is 2 g/mol.
Mass of H2 = 5.37 mol H2 x 2 g/mol = 10.74 g.
Therefore, you would require approximately 10.74 grams of hydrogen to react with 50 grams of nitrogen.
Step-by-Step Solution:
Step 1: Write a balanced chemical equation.
N2 + 3H2 --> 2NH3
Step 2: Convert grams of nitrogen to moles.
molar mass of nitrogen (N2) = 2 x atomic mass of nitrogen = 2 x 14 = 28 g/mol
moles of N2 = mass of N2 / molar mass of N2
moles of N2 = 50 g / 28 g/mol = 1.79 mol
Step 3: Use the balanced equation to convert moles of N2 to moles of H2.
According to the balanced equation, there are 3 moles of H2 for every 1 mole of N2.
moles of H2 = moles of N2 x (3 moles of H2 / 1 mole of N2)
moles of H2 = 1.79 mol x (3 mol H2 / 1 mol N2) = 5.37 mol
Step 4: Convert moles of H2 to grams of H2.
molar mass of H2 = 2 g/mol
grams of H2 = moles of H2 x molar mass of H2
grams of H2 = 5.37 mol x 2 g/mol = 10.74 g
Therefore, 10.74 grams of hydrogen are needed to react with 50 grams of nitrogen.