Posted by
**marie** on
.

3

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2

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1 + 1

-- --

3 x

I assume you mean (3/2)/[(1/3) + (1/x)]

You could rewrite the denominator as

[(1/3) + (1/x)] = (x + 3)/(3x)

Which would lead to

(3/2)/[(1/3) + (1/x)]

= (3/2)*(3x)/(x+3)= (9/2)[x/(x+3)]

Thank you