Wednesday
July 1, 2015

Homework Help: phys

Posted by slien on Monday, June 19, 2006 at 7:47pm.

a projectile is launched at 35 degrees above the horizontal with an initial velocity of 120m/s. What is the projectile's speed 3 seconds later?


Figure the new vertical velocity at t=3. then the speed as equal to sqrt(Vv^2+ Vh^2)

The other way to do this is figure how high it travels in three seconds, then use the fact that

Kineticenergy=initialKE- change in PE.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members