posted by slien on .
a projectile is launched at 35 degrees above the horizontal with an initial velocity of 120m/s. What is the projectile's speed 3 seconds later?
Figure the new vertical velocity at t=3. then the speed as equal to sqrt(Vv^2+ Vh^2)
The other way to do this is figure how high it travels in three seconds, then use the fact that
Kineticenergy=initialKE- change in PE.