Posted by **slien** on Monday, June 19, 2006 at 7:47pm.

a projectile is launched at 35 degrees above the horizontal with an initial velocity of 120m/s. What is the projectile's speed 3 seconds later?

Figure the new vertical velocity at t=3. then the speed as equal to sqrt(Vv^2+ Vh^2)

The other way to do this is figure how high it travels in three seconds, then use the fact that

Kineticenergy=initialKE- change in PE.

- phys -
**Anonymous**, Thursday, September 26, 2013 at 3:09pm
cfghdf

## Answer this Question

## Related Questions

- Physics- i need to know how to do these problems - Two projectiles are launched ...
- Physics - A projectile is launched with an initial speed of 80.0m/s at an angle ...
- Physics - A projectile is launched with an initial speed of 40m/s at an angle of...
- Physics Projectile Motion - A projectile is launched at ground level with an ...
- Physics - A projectile is launched at an angle of 34.0o above the horizontal. ...
- Physics - We have a projectile launched upward with an initial horizontal ...
- Physics - A projectile is fired with an initial speed of 28.0 m/s at an angle of...
- physics - A projectile is launched at an angle of 58.5 degrees above the ...
- Physics - a projectile has an initial velocity of 15.0 m/s at an angle of 30 ...
- Physics - A projectile is launched at ground level with an initial speed of 51....

More Related Questions